Write a balanced equation for the formation of CO2(g) from C(s)
and O2(g). Calculate change for this reaction using the following
data at 25deg celcius
C(s)+1/2 O2(g)àCO(g) change in H= -111 kJ
CO(g) + ½ (g)àCO2(g) change in H= -394 kJ
Is this endothermic or exothermic?
Explain how change in temperature would be affected of a greater
amount of surrounding solvent (water) is used, assuming the mass of
salt remains constant?
Explain how q-reaction would be affected of a greater amount of
surrounding solvent (water) is used? Explain
Tony SparkEnlightened
Concepts and reasonBalanced chemical equation:In a balanced chemical equation, the number of the coefficient of reactants is equal to those of products.Enthalpy of formation:It is energy required for the formation of any compound. First, write a balanced chemical equation for the formation of CO2{rm{C}}{{rm{O}}_{rm{2}}}CO2 , Then the enthalpy of formation is calculated by the given reactions and their respective enthalpies.Endothermic reaction:In this reaction energy or heat is being absorbed.Exothermic reaction:In this reaction energy or heat is being released.
FundamentalsBalancing of the equation: C(s)+12O2(g)⟶CO(g){rm{C}}left( s right) + frac{1}{2}{rm{ }}{{rm{O}}_{rm{2}}}left( g right)longrightarrow{{}}{rm{CO}}left( g right)C(s)+21O2(g)⟶CO(g) As the number of the coefficient of reactants is equal to the number of the coefficient of products.Enthalpy change:It is the name given to the amount of heat released or absorbed at constant pressure.Elevation in boiling point: ΔT=iKbmDelta T{rm{ = }}i{K_{rm{b}}}mΔT=iKbm …… (I)Here iii is van’thoff factor, Kb{K_{rm{b}}}Kb is the molal boiling point constant, mmm is molalityDepression in freezing point: ΔT=iKfmDelta T{rm{ = }}i{K_{rm{f}}}mΔT=iKfm …… (II)Here, Kf{K_{rm{f}}}Kf the molal freezing point constant iii is the van’thoff factor, mmm is molalityThe heat of reaction:It is an enthalpy change of a chemical reaction that occurs a constant pressure. Q=mCpΔTQ{rm{ }} = {rm{ }}m{rm{ }}{C_{rm{p}}}Delta TQ=mCpΔT …… (III)Here, QQQ is heat transfer, Cp{C_{rm{p}}}Cp is standard heat capacity, ΔT{rm{Delta T}}ΔT is a temperature difference, mmm is the mass flow rateMolality:It is defined as a number of moles of solute per kilogram of solvent. m=molesofsolutemassofsolvent(Kg){rm{m = }}frac{{{rm{moles of solute}}}}{{{rm{mass of solvent (Kg)}}}}m=massofsolvent(Kg)molesofsolute …… (IV)
Step 1
(1)The balanced chemical equation is: C(s)+O2(g)→CO2(g)Cleft( s right) + {O_2}left( g right) to C{O_2}left( g right)C(s)+O2(g)→CO2(g) The given chemical equations and their respective enthalpies: C(s)+12O2(g)→CO(g)ΔH=111kJCO(s)+12O2(g)→CO2(g)ΔH=−394kJbegin{array}{l}{rm{C}}left( s right){rm{ + }}frac{{rm{1}}}{{rm{2}}}{rm{ }}{{rm{O}}_{rm{2}}}left( g right) to cancel{{{rm{CO}}left( g right)}}{rm{ }}Delta H{rm{ = 111 kJ}}cancel{{{rm{CO}}left( s right)}}{rm{ + }}frac{{rm{1}}}{{rm{2}}}{rm{ }}{{rm{O}}_{rm{2}}}left( g right) to {rm{C}}{{rm{O}}_2}left( g right){rm{ }}Delta H{rm{ = – 394 kJ}}end{array}C(s)+2<span class="pstrut" style="height